2213411130041 has 4 divisors (see below), whose sum is σ = 2234900558592. Its totient is φ = 2191921701492.

The previous prime is 2213411129959. The next prime is 2213411130101. The reversal of 2213411130041 is 1400311143122.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2213411130041 - 2²² = 2213406935737 is a prime.

It is a super-2 number, since 2×2213411130041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2213411129989 and 2213411130016.

It is not an unprimeable number, because it can be changed into a prime (2213411130341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10744714121 + ... + 10744714326.

It is an arithmetic number, because the mean of its divisors is an integer number (558725139648).

Almost surely, 2^{2213411130041} is an apocalyptic number.

It is an amenable number.

2213411130041 is a deficient number, since it is larger than the sum of its proper divisors (21489428551).

2213411130041 is a wasteful number, since it uses less digits than its factorization.

2213411130041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21489428550.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 2213411130041 its reverse (1400311143122), we get a palindrome (3613722273163).

The spelling of 2213411130041 in words is "two trillion, two hundred thirteen billion, four hundred eleven million, one hundred thirty thousand, forty-one".