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2221101111113 is a prime number
BaseRepresentation
bin100000010100100011111…
…100010101011101001001
321212100001100121001012022
4200110203330111131021
5242342303341023423
64420205413054225
7316316645640323
oct40244374253511
97770040531168
102221101111113
11786a66745095
122ba56a327375
131315ab40a7c1
14797051a4613
153cb98bc2dc8
hex20523f15749

2221101111113 has 2 divisors, whose sum is σ = 2221101111114. Its totient is φ = 2221101111112.

The previous prime is 2221101111011. The next prime is 2221101111127. The reversal of 2221101111113 is 3111111011222.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2207164836409 + 13936274704 = 1485653^2 + 118052^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2221101111113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2221101111091 and 2221101111100.

It is not a weakly prime, because it can be changed into another prime (2221101111193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1110550555556 + 1110550555557.

It is an arithmetic number, because the mean of its divisors is an integer number (1110550555557).

Almost surely, 22221101111113 is an apocalyptic number.

It is an amenable number.

2221101111113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2221101111113 is an equidigital number, since it uses as much as digits as its factorization.

2221101111113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 2221101111113 its reverse (3111111011222), we get a palindrome (5332212122335).

The spelling of 2221101111113 in words is "two trillion, two hundred twenty-one billion, one hundred one million, one hundred eleven thousand, one hundred thirteen".