Base | Representation |
---|---|
bin | 1010000110011111001001… |
… | …00110010010110001010111 |
3 | 2220122112220220111111221221 |
4 | 11003033210212102301113 |
5 | 10402414422422144343 |
6 | 115124321250151211 |
7 | 4451562413164225 |
oct | 503174446226127 |
9 | 86575826444857 |
10 | 22213111131223 |
11 | 7094589158a61 |
12 | 25a9071b82507 |
13 | c518c227918c |
14 | 56b198205b15 |
15 | 287c3238c5ed |
hex | 1433e4992c57 |
22213111131223 has 2 divisors, whose sum is σ = 22213111131224. Its totient is φ = 22213111131222.
The previous prime is 22213111131217. The next prime is 22213111131307. The reversal of 22213111131223 is 32213111131222.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 22213111131223 - 213 = 22213111123031 is a prime.
It is a super-3 number, since 3×222131111312233 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22213171131223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11106555565611 + 11106555565612.
It is an arithmetic number, because the mean of its divisors is an integer number (11106555565612).
Almost surely, 222213111131223 is an apocalyptic number.
22213111131223 is a deficient number, since it is larger than the sum of its proper divisors (1).
22213111131223 is an equidigital number, since it uses as much as digits as its factorization.
22213111131223 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864, while the sum is 25.
Adding to 22213111131223 its reverse (32213111131222), we get a palindrome (54426222262445).
Subtracting 22213111131223 from its reverse (32213111131222), we obtain a palindrome (9999999999999).
The spelling of 22213111131223 in words is "twenty-two trillion, two hundred thirteen billion, one hundred eleven million, one hundred thirty-one thousand, two hundred twenty-three".
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