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2223110000113 = 12231817751431
BaseRepresentation
bin100000010110011011101…
…011101000110111110001
321212112020100200011211121
4200112123223220313301
5242410412130000423
64421141014342241
7316420511133502
oct40263353506761
97775210604747
102223110000113
117878a7703132
122baa2b05a981
1313183b677b12
1479855cd4ba9
153cc6523e45d
hex2059bae8df1

2223110000113 has 4 divisors (see below), whose sum is σ = 2224927752768. Its totient is φ = 2221292247460.

The previous prime is 2223110000053. The next prime is 2223110000147. The reversal of 2223110000113 is 3110000113222.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2223110000113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2223110004113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 908874493 + ... + 908876938.

It is an arithmetic number, because the mean of its divisors is an integer number (556231938192).

Almost surely, 22223110000113 is an apocalyptic number.

It is an amenable number.

2223110000113 is a deficient number, since it is larger than the sum of its proper divisors (1817752655).

2223110000113 is a wasteful number, since it uses less digits than its factorization.

2223110000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1817752654.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 2223110000113 its reverse (3110000113222), we get a palindrome (5333110113335).

The spelling of 2223110000113 in words is "two trillion, two hundred twenty-three billion, one hundred ten million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 1223 1817751431 2223110000113