Base | Representation |
---|---|
bin | 110010100100100010101101… |
… | …111110100011110101010011 |
3 | 1002011111112010121010211022201 |
4 | 302210202231332203311103 |
5 | 213123010324330023011 |
6 | 2105011204230344031 |
7 | 64563563000122255 |
oct | 6244425576436523 |
9 | 1064445117124281 |
10 | 222413505314131 |
11 | 649600464949aa |
12 | 20b41288abb017 |
13 | 971467140cb41 |
14 | 3cccc2a3d9cd5 |
15 | 1aaa7442b5cc1 |
hex | ca48adfa3d53 |
222413505314131 has 2 divisors, whose sum is σ = 222413505314132. Its totient is φ = 222413505314130.
The previous prime is 222413505314129. The next prime is 222413505314381. The reversal of 222413505314131 is 131413505314222.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 222413505314131 - 21 = 222413505314129 is a prime.
It is a super-2 number, since 2×2224135053141312 (a number of 29 digits) contains 22 as substring.
Together with 222413505314129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (222413502314131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111206752657065 + 111206752657066.
It is an arithmetic number, because the mean of its divisors is an integer number (111206752657066).
Almost surely, 2222413505314131 is an apocalyptic number.
222413505314131 is a deficient number, since it is larger than the sum of its proper divisors (1).
222413505314131 is an equidigital number, since it uses as much as digits as its factorization.
222413505314131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 37.
Subtracting from 222413505314131 its reverse (131413505314222), we obtain a palindrome (90999999999909).
The spelling of 222413505314131 in words is "two hundred twenty-two trillion, four hundred thirteen billion, five hundred five million, three hundred fourteen thousand, one hundred thirty-one".
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