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22255014113 = 71313450903
BaseRepresentation
bin10100101110100000…
…001001000011100001
32010102222201212001222
4110232200021003201
5331034240422423
614120202104425
71415333333033
oct245640110341
963388655058
1022255014113
119490414552
1243911ab115
13213892ba07
1411119a3c53
158a3c033c8
hex52e8090e1

22255014113 has 4 divisors (see below), whose sum is σ = 22568465088. Its totient is φ = 21941563140.

The previous prime is 22255014097. The next prime is 22255014121. The reversal of 22255014113 is 31141055222.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 22255014113 - 24 = 22255014097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (22255014413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156725381 + ... + 156725522.

It is an arithmetic number, because the mean of its divisors is an integer number (5642116272).

Almost surely, 222255014113 is an apocalyptic number.

It is an amenable number.

22255014113 is a deficient number, since it is larger than the sum of its proper divisors (313450975).

22255014113 is an equidigital number, since it uses as much as digits as its factorization.

22255014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 313450974.

The product of its (nonzero) digits is 2400, while the sum is 26.

Adding to 22255014113 its reverse (31141055222), we get a palindrome (53396069335).

The spelling of 22255014113 in words is "twenty-two billion, two hundred fifty-five million, fourteen thousand, one hundred thirteen".

Divisors: 1 71 313450903 22255014113