Base | Representation |
---|---|
bin | 10100110001110110… |
… | …111001001010110001 |
3 | 2010120220122222111212 |
4 | 110301312321022301 |
5 | 331143143410001 |
6 | 14125532445505 |
7 | 1416616002011 |
oct | 246166711261 |
9 | 63526588455 |
10 | 22311310001 |
11 | 950a175482 |
12 | 43a8019895 |
13 | 21474ac9a6 |
14 | 1119259c41 |
15 | 8a8b237bb |
hex | 531db92b1 |
22311310001 has 2 divisors, whose sum is σ = 22311310002. Its totient is φ = 22311310000.
The previous prime is 22311309991. The next prime is 22311310003. The reversal of 22311310001 is 10001311322.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 22297656976 + 13653025 = 149324^2 + 3695^2 .
It is a cyclic number.
It is not a de Polignac number, because 22311310001 - 214 = 22311293617 is a prime.
It is a super-3 number, since 3×223113100013 (a number of 32 digits) contains 333 as substring.
Together with 22311310003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (22311310003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11155655000 + 11155655001.
It is an arithmetic number, because the mean of its divisors is an integer number (11155655001).
Almost surely, 222311310001 is an apocalyptic number.
It is an amenable number.
22311310001 is a deficient number, since it is larger than the sum of its proper divisors (1).
22311310001 is an equidigital number, since it uses as much as digits as its factorization.
22311310001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 22311310001 its reverse (10001311322), we get a palindrome (32312621323).
The spelling of 22311310001 in words is "twenty-two billion, three hundred eleven million, three hundred ten thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •