Search a number
-
+
223125004433 is a prime number
BaseRepresentation
bin1100111111001101001…
…0010110000010010001
3210022220222001121221002
43033303102112002101
512123430000120213
6250300251111345
722056150150002
oct3176322260221
9708828047832
10223125004433
1186699280311
12372b0142555
131806b268056
14ab2942d1a9
155c0d727658
hex33f3496091

223125004433 has 2 divisors, whose sum is σ = 223125004434. Its totient is φ = 223125004432.

The previous prime is 223125004409. The next prime is 223125004441. The reversal of 223125004433 is 334400521322.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 200017356289 + 23107648144 = 447233^2 + 152012^2 .

It is a cyclic number.

It is not a de Polignac number, because 223125004433 - 28 = 223125004177 is a prime.

It is a super-3 number, since 3×2231250044333 (a number of 35 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 223125004396 and 223125004405.

It is not a weakly prime, because it can be changed into another prime (223125004493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111562502216 + 111562502217.

It is an arithmetic number, because the mean of its divisors is an integer number (111562502217).

Almost surely, 2223125004433 is an apocalyptic number.

It is an amenable number.

223125004433 is a deficient number, since it is larger than the sum of its proper divisors (1).

223125004433 is an equidigital number, since it uses as much as digits as its factorization.

223125004433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 29.

Adding to 223125004433 its reverse (334400521322), we get a palindrome (557525525755).

The spelling of 223125004433 in words is "two hundred twenty-three billion, one hundred twenty-five million, four thousand, four hundred thirty-three".