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223125245213407 is a prime number
BaseRepresentation
bin110010101110111001100100…
…111110110011101011011111
31002021000120020222022220021221
4302232321210332303223133
5213221141000233312112
62110314153402434211
764666160402341345
oct6256714476635337
91067016228286257
10223125245213407
1165104981072699
1221037201202967
13976680ab73534
143d15468973995
151abdeedd61e07
hexcaee64fb3adf

223125245213407 has 2 divisors, whose sum is σ = 223125245213408. Its totient is φ = 223125245213406.

The previous prime is 223125245213369. The next prime is 223125245213417. The reversal of 223125245213407 is 704312542521322.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-223125245213407 is a prime.

It is a super-3 number, since 3×2231252452134073 (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (223125245213417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 111562622606703 + 111562622606704.

It is an arithmetic number, because the mean of its divisors is an integer number (111562622606704).

Almost surely, 2223125245213407 is an apocalyptic number.

223125245213407 is a deficient number, since it is larger than the sum of its proper divisors (1).

223125245213407 is an equidigital number, since it uses as much as digits as its factorization.

223125245213407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 806400, while the sum is 43.

Adding to 223125245213407 its reverse (704312542521322), we get a palindrome (927437787734729).

The spelling of 223125245213407 in words is "two hundred twenty-three trillion, one hundred twenty-five billion, two hundred forty-five million, two hundred thirteen thousand, four hundred seven".