Base | Representation |
---|---|
bin | 1010001001011001100111… |
… | …01010111101000111111111 |
3 | 2221000010022210202122011021 |
4 | 11010230303222331013333 |
5 | 10411034434313014101 |
6 | 115242315213405011 |
7 | 4462035304426534 |
oct | 504546352750777 |
9 | 87003283678137 |
10 | 22313222001151 |
11 | 7122a9112a2a4 |
12 | 2604550a99767 |
13 | c5b187a36c13 |
14 | 571d73c86d8b |
15 | 28a6411c75a1 |
hex | 144b33abd1ff |
22313222001151 has 2 divisors, whose sum is σ = 22313222001152. Its totient is φ = 22313222001150.
The previous prime is 22313222001121. The next prime is 22313222001167. The reversal of 22313222001151 is 15110022231322.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22313222001151 - 29 = 22313222000639 is a prime.
It is a super-3 number, since 3×223132220011513 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22313222001121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11156611000575 + 11156611000576.
It is an arithmetic number, because the mean of its divisors is an integer number (11156611000576).
Almost surely, 222313222001151 is an apocalyptic number.
22313222001151 is a deficient number, since it is larger than the sum of its proper divisors (1).
22313222001151 is an equidigital number, since it uses as much as digits as its factorization.
22313222001151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 22313222001151 its reverse (15110022231322), we get a palindrome (37423244232473).
The spelling of 22313222001151 in words is "twenty-two trillion, three hundred thirteen billion, two hundred twenty-two million, one thousand, one hundred fifty-one".
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