22400011313 has 4 divisors (see below), whose sum is σ = 22683555840. Its totient is φ = 22116466788.

The previous prime is 22400011253. The next prime is 22400011363. The reversal of 22400011313 is 31311000422.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-22400011313 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 22400011291 and 22400011300.

It is not an unprimeable number, because it can be changed into a prime (22400011363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141772145 + ... + 141772302.

It is an arithmetic number, because the mean of its divisors is an integer number (5670888960).

Almost surely, 2^22400011313 is an apocalyptic number.

It is an amenable number.

22400011313 is a deficient number, since it is larger than the sum of its proper divisors (283544527).

22400011313 is an equidigital number, since it uses as much as digits as its factorization.

22400011313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 283544526.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 22400011313 its reverse (31311000422), we get a palindrome (53711011735).

The spelling of 22400011313 in words is "twenty-two billion, four hundred million, eleven thousand, three hundred thirteen".