Base | Representation |
---|---|
bin | 1010001011111111000000… |
… | …00010111101001110110101 |
3 | 2221022121111211021222121101 |
4 | 11011333200002331032311 |
5 | 10414013310402220432 |
6 | 115351202015450101 |
7 | 4501330526250634 |
oct | 505774002751665 |
9 | 87277454258541 |
10 | 22402013320117 |
11 | 7157705555442 |
12 | 26197b0b26931 |
13 | c66668315602 |
14 | 57639843551b |
15 | 28cadb3a14e7 |
hex | 145fe00bd3b5 |
22402013320117 has 2 divisors, whose sum is σ = 22402013320118. Its totient is φ = 22402013320116.
The previous prime is 22402013320111. The next prime is 22402013320153. The reversal of 22402013320117 is 71102331020422.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22319870320881 + 82142999236 = 4724391^2 + 286606^2 .
It is a cyclic number.
It is not a de Polignac number, because 22402013320117 - 23 = 22402013320109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22402013320111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11201006660058 + 11201006660059.
It is an arithmetic number, because the mean of its divisors is an integer number (11201006660059).
Almost surely, 222402013320117 is an apocalyptic number.
It is an amenable number.
22402013320117 is a deficient number, since it is larger than the sum of its proper divisors (1).
22402013320117 is an equidigital number, since it uses as much as digits as its factorization.
22402013320117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 22402013320117 its reverse (71102331020422), we get a palindrome (93504344340539).
The spelling of 22402013320117 in words is "twenty-two trillion, four hundred two billion, thirteen million, three hundred twenty thousand, one hundred seventeen".
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