Base | Representation |
---|---|
bin | 1010001100010100000101… |
… | …00101100101111010110011 |
3 | 2221100200201112002020122122 |
4 | 11012022002211211322303 |
5 | 10414210000020241001 |
6 | 115400313004424455 |
7 | 4502211134435633 |
oct | 506120245457263 |
9 | 87320645066578 |
10 | 22413330243251 |
11 | 7161492676282 |
12 | 261ba2ab4812b |
13 | c6774cab482c |
14 | 576b4d4426c3 |
15 | 28d04eb93b1b |
hex | 146282965eb3 |
22413330243251 has 2 divisors, whose sum is σ = 22413330243252. Its totient is φ = 22413330243250.
The previous prime is 22413330243181. The next prime is 22413330243253. The reversal of 22413330243251 is 15234203331422.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22413330243251 - 214 = 22413330226867 is a prime.
Together with 22413330243253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (22413330243253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11206665121625 + 11206665121626.
It is an arithmetic number, because the mean of its divisors is an integer number (11206665121626).
Almost surely, 222413330243251 is an apocalyptic number.
22413330243251 is a deficient number, since it is larger than the sum of its proper divisors (1).
22413330243251 is an equidigital number, since it uses as much as digits as its factorization.
22413330243251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 22413330243251 its reverse (15234203331422), we get a palindrome (37647533574673).
The spelling of 22413330243251 in words is "twenty-two trillion, four hundred thirteen billion, three hundred thirty million, two hundred forty-three thousand, two hundred fifty-one".
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