Base | Representation |
---|---|
bin | 1010001100010100010011… |
… | …11010110101110110010011 |
3 | 2221100201001002112211201121 |
4 | 11012022021322311312103 |
5 | 10414210223013112120 |
6 | 115400333121143111 |
7 | 4502214160136644 |
oct | 506121172656623 |
9 | 87321032484647 |
10 | 22413453254035 |
11 | 7161546054088 |
12 | 261ba6418aa97 |
13 | c6776c423c8c |
14 | 576b619036cb |
15 | 28d05a8915aa |
hex | 146289eb5d93 |
22413453254035 has 32 divisors (see below), whose sum is σ = 27935684352000. Its totient is φ = 17242812518400.
The previous prime is 22413453254009. The next prime is 22413453254047. The reversal of 22413453254035 is 53045235431422.
It is not a de Polignac number, because 22413453254035 - 29 = 22413453253523 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22413453253982 and 22413453254000.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 52693891 + ... + 53117539.
It is an arithmetic number, because the mean of its divisors is an integer number (872990136000).
Almost surely, 222413453254035 is an apocalyptic number.
22413453254035 is a deficient number, since it is larger than the sum of its proper divisors (5522231097965).
22413453254035 is a wasteful number, since it uses less digits than its factorization.
22413453254035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 425151.
The product of its (nonzero) digits is 1728000, while the sum is 43.
Adding to 22413453254035 its reverse (53045235431422), we get a palindrome (75458688685457).
The spelling of 22413453254035 in words is "twenty-two trillion, four hundred thirteen billion, four hundred fifty-three million, two hundred fifty-four thousand, thirty-five".
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