Base | Representation |
---|---|
bin | 1010001100010100010011… |
… | …11010110101110110100011 |
3 | 2221100201001002112211202012 |
4 | 11012022021322311312203 |
5 | 10414210223013112201 |
6 | 115400333121143135 |
7 | 4502214160136666 |
oct | 506121172656643 |
9 | 87321032484665 |
10 | 22413453254051 |
11 | 71615460540a2 |
12 | 261ba6418aaab |
13 | c6776c423ca2 |
14 | 576b619036dd |
15 | 28d05a8915bb |
hex | 146289eb5da3 |
22413453254051 has 2 divisors, whose sum is σ = 22413453254052. Its totient is φ = 22413453254050.
The previous prime is 22413453254047. The next prime is 22413453254077. The reversal of 22413453254051 is 15045235431422.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 22413453254051 - 22 = 22413453254047 is a prime.
It is not a weakly prime, because it can be changed into another prime (22413453254351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11206726627025 + 11206726627026.
It is an arithmetic number, because the mean of its divisors is an integer number (11206726627026).
Almost surely, 222413453254051 is an apocalyptic number.
22413453254051 is a deficient number, since it is larger than the sum of its proper divisors (1).
22413453254051 is an equidigital number, since it uses as much as digits as its factorization.
22413453254051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576000, while the sum is 41.
Adding to 22413453254051 its reverse (15045235431422), we get a palindrome (37458688685473).
The spelling of 22413453254051 in words is "twenty-two trillion, four hundred thirteen billion, four hundred fifty-three million, two hundred fifty-four thousand, fifty-one".
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