Base | Representation |
---|---|
bin | 10100111001100101… |
… | …101000010111000001 |
3 | 2010220221201001002021 |
4 | 110321211220113001 |
5 | 331424344034213 |
6 | 14150444321441 |
7 | 1423052242033 |
oct | 247145502701 |
9 | 63827631067 |
10 | 22441002433 |
11 | 95763a7303 |
12 | 4423543281 |
13 | 216831b485 |
14 | 112c579c53 |
15 | 8b51e0d8d |
hex | 5399685c1 |
22441002433 has 4 divisors (see below), whose sum is σ = 22441816240. Its totient is φ = 22440188628.
The previous prime is 22441002383. The next prime is 22441002449. The reversal of 22441002433 is 33420014422.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 22441002433 - 217 = 22440871361 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 22441002398 and 22441002407.
It is not an unprimeable number, because it can be changed into a prime (22441003433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 364035 + ... + 421192.
It is an arithmetic number, because the mean of its divisors is an integer number (5610454060).
Almost surely, 222441002433 is an apocalyptic number.
It is an amenable number.
22441002433 is a deficient number, since it is larger than the sum of its proper divisors (813807).
22441002433 is an equidigital number, since it uses as much as digits as its factorization.
22441002433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 813806.
The product of its (nonzero) digits is 4608, while the sum is 25.
Adding to 22441002433 its reverse (33420014422), we get a palindrome (55861016855).
The spelling of 22441002433 in words is "twenty-two billion, four hundred forty-one million, two thousand, four hundred thirty-three".
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