Base | Representation |
---|---|
bin | 110011001010010110000111… |
… | …011101001011100111100111 |
3 | 1002111200212112100221211201001 |
4 | 303022112013131023213213 |
5 | 213443041132421302241 |
6 | 2114320434251414131 |
7 | 65252350061521105 |
oct | 6312260735134747 |
9 | 1074625470854631 |
10 | 225011314244071 |
11 | 65771842948983 |
12 | 212a0849a54347 |
13 | 98726256a8844 |
14 | 3d7c86a138c75 |
15 | 1b030d9aaa431 |
hex | cca58774b9e7 |
225011314244071 has 2 divisors, whose sum is σ = 225011314244072. Its totient is φ = 225011314244070.
The previous prime is 225011314244023. The next prime is 225011314244081. The reversal of 225011314244071 is 170442413110522.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 225011314244071 - 211 = 225011314242023 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 225011314244071.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (225011314244011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 112505657122035 + 112505657122036.
It is an arithmetic number, because the mean of its divisors is an integer number (112505657122036).
Almost surely, 2225011314244071 is an apocalyptic number.
225011314244071 is a deficient number, since it is larger than the sum of its proper divisors (1).
225011314244071 is an equidigital number, since it uses as much as digits as its factorization.
225011314244071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 53760, while the sum is 37.
Adding to 225011314244071 its reverse (170442413110522), we get a palindrome (395453727354593).
The spelling of 225011314244071 in words is "two hundred twenty-five trillion, eleven billion, three hundred fourteen million, two hundred forty-four thousand, seventy-one".
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