Base | Representation |
---|---|
bin | 110011001100011010001011… |
… | …110100111011001111110111 |
3 | 1002112012102120011022201220202 |
4 | 303030122023310323033313 |
5 | 214002402043100414403 |
6 | 2114505525513151115 |
7 | 65265530146346441 |
oct | 6314321364731767 |
9 | 1075172504281822 |
10 | 225153121498103 |
11 | 658169a23a0797 |
12 | 213042249bb49b |
13 | 9882b047ca606 |
14 | 3d8567d7ab491 |
15 | 1b06b392b9688 |
hex | ccc68bd3b3f7 |
225153121498103 has 2 divisors, whose sum is σ = 225153121498104. Its totient is φ = 225153121498102.
The previous prime is 225153121498091. The next prime is 225153121498111. The reversal of 225153121498103 is 301894121351522.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 225153121498103 - 244 = 207560935453687 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (225153121498003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 112576560749051 + 112576560749052.
It is an arithmetic number, because the mean of its divisors is an integer number (112576560749052).
Almost surely, 2225153121498103 is an apocalyptic number.
225153121498103 is a deficient number, since it is larger than the sum of its proper divisors (1).
225153121498103 is an equidigital number, since it uses as much as digits as its factorization.
225153121498103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 518400, while the sum is 47.
The spelling of 225153121498103 in words is "two hundred twenty-five trillion, one hundred fifty-three billion, one hundred twenty-one million, four hundred ninety-eight thousand, one hundred three".
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