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225153121500145 = 545030624300029
BaseRepresentation
bin110011001100011010001011…
…110100111011101111110001
31002112012102120011022211201101
4303030122023310323233301
5214002402043101001040
62114505525513204401
765265530146355416
oct6314321364735761
91075172504284641
10225153121500145
11658169a23a2283
1221304224a00701
139882b047cb517
143d8567d7ac10d
151b06b392ba09a
hexccc68bd3bbf1

225153121500145 has 4 divisors (see below), whose sum is σ = 270183745800180. Its totient is φ = 180122497200112.

The previous prime is 225153121500089. The next prime is 225153121500169. The reversal of 225153121500145 is 541005121351522.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 134145318380544 + 91007803119601 = 11582112^2 + 9539801^2 .

It is a cyclic number.

It is not a de Polignac number, because 225153121500145 - 221 = 225153119402993 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22515312150010 + ... + 22515312150019.

It is an arithmetic number, because the mean of its divisors is an integer number (67545936450045).

Almost surely, 2225153121500145 is an apocalyptic number.

It is an amenable number.

225153121500145 is a deficient number, since it is larger than the sum of its proper divisors (45030624300035).

225153121500145 is an equidigital number, since it uses as much as digits as its factorization.

225153121500145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45030624300034.

The product of its (nonzero) digits is 60000, while the sum is 37.

Adding to 225153121500145 its reverse (541005121351522), we get a palindrome (766158242851667).

The spelling of 225153121500145 in words is "two hundred twenty-five trillion, one hundred fifty-three billion, one hundred twenty-one million, five hundred thousand, one hundred forty-five".

Divisors: 1 5 45030624300029 225153121500145