Base | Representation |
---|---|
bin | 100000111000111010010… |
… | …011101011100100011001 |
3 | 22000001210102021122000022 |
4 | 200320322103223210121 |
5 | 244012222021113132 |
6 | 4450142335520225 |
7 | 322201103552153 |
oct | 40707223534431 |
9 | 8001712248008 |
10 | 2260131035417 |
11 | 7a1575058982 |
12 | 306041389075 |
13 | 13518b4cc578 |
14 | 7b5689b3ad3 |
15 | 3dbd0439e12 |
hex | 20e3a4eb919 |
2260131035417 has 2 divisors, whose sum is σ = 2260131035418. Its totient is φ = 2260131035416.
The previous prime is 2260131035413. The next prime is 2260131035419. The reversal of 2260131035417 is 7145301310622.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2196356604121 + 63774431296 = 1482011^2 + 252536^2 .
It is a cyclic number.
It is not a de Polignac number, because 2260131035417 - 22 = 2260131035413 is a prime.
Together with 2260131035419, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2260131035413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1130065517708 + 1130065517709.
It is an arithmetic number, because the mean of its divisors is an integer number (1130065517709).
Almost surely, 22260131035417 is an apocalyptic number.
It is an amenable number.
2260131035417 is a deficient number, since it is larger than the sum of its proper divisors (1).
2260131035417 is an equidigital number, since it uses as much as digits as its factorization.
2260131035417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30240, while the sum is 35.
The spelling of 2260131035417 in words is "two trillion, two hundred sixty billion, one hundred thirty-one million, thirty-five thousand, four hundred seventeen".
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