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230001113 = 886725939
BaseRepresentation
bin11011011010110…
…00100111011001
3121000210021012202
431231120213121
5432340013423
634453415545
75461656116
oct1555304731
9530707182
10230001113
11108914271
126503a5b5
133885c944
142279190d
15152d3728
hexdb589d9

230001113 has 4 divisors (see below), whose sum is σ = 230035920. Its totient is φ = 229966308.

The previous prime is 230001097. The next prime is 230001119. The reversal of 230001113 is 311100032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 230001113 - 24 = 230001097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 230001094 and 230001103.

It is not an unprimeable number, because it can be changed into a prime (230001119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4103 + ... + 21836.

It is an arithmetic number, because the mean of its divisors is an integer number (57508980).

Almost surely, 2230001113 is an apocalyptic number.

It is an amenable number.

230001113 is a deficient number, since it is larger than the sum of its proper divisors (34807).

230001113 is an equidigital number, since it uses as much as digits as its factorization.

230001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34806.

The product of its (nonzero) digits is 18, while the sum is 11.

The square root of 230001113 is about 15165.7875825821. The cubic root of 230001113 is about 612.6935558210.

Adding to 230001113 its reverse (311100032), we get a palindrome (541101145).

The spelling of 230001113 in words is "two hundred thirty million, one thousand, one hundred thirteen".

Divisors: 1 8867 25939 230001113