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23001000313 = 127431804991
BaseRepresentation
bin10101011010111101…
…110110100101111001
32012100222102212202111
4111122331312211321
5334101224002223
614322211132321
71442662163644
oct253275664571
965328385674
1023001000313
119833512a75
12455aba40a1
13222734c575
141182aaca5b
158e945b30d
hex55af76979

23001000313 has 4 divisors (see below), whose sum is σ = 23002818048. Its totient is φ = 22999182580.

The previous prime is 23001000299. The next prime is 23001000361. The reversal of 23001000313 is 31300010032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23001000313 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23001000293 and 23001000302.

It is not an unprimeable number, because it can be changed into a prime (23001000413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 889753 + ... + 915238.

It is an arithmetic number, because the mean of its divisors is an integer number (5750704512).

Almost surely, 223001000313 is an apocalyptic number.

It is an amenable number.

23001000313 is a deficient number, since it is larger than the sum of its proper divisors (1817735).

23001000313 is a wasteful number, since it uses less digits than its factorization.

23001000313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1817734.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 23001000313 its reverse (31300010032), we get a palindrome (54301010345).

The spelling of 23001000313 in words is "twenty-three billion, one million, three hundred thirteen", and thus it is an aban number.

Divisors: 1 12743 1804991 23001000313