Base | Representation |
---|---|
bin | 10101011011000011… |
… | …001111000110101001 |
3 | 2012101002002120110012 |
4 | 111123003033012221 |
5 | 334102104131213 |
6 | 14322301301305 |
7 | 1443010162001 |
oct | 253303170651 |
9 | 65332076405 |
10 | 23002411433 |
11 | 9834297191 |
12 | 455b564835 |
13 | 2227724951 |
14 | 1182d59001 |
15 | 8e96394a8 |
hex | 55b0cf1a9 |
23002411433 has 8 divisors (see below), whose sum is σ = 23083040448. Its totient is φ = 22921917424.
The previous prime is 23002411409. The next prime is 23002411441. The reversal of 23002411433 is 33411420032.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 23002411433 - 28 = 23002411177 is a prime.
It is a super-2 number, since 2×230024114332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23002411399 and 23002411408.
It is not an unprimeable number, because it can be changed into a prime (23002411633) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 313835 + ... + 380127.
It is an arithmetic number, because the mean of its divisors is an integer number (2885380056).
Almost surely, 223002411433 is an apocalyptic number.
It is an amenable number.
23002411433 is a deficient number, since it is larger than the sum of its proper divisors (80629015).
23002411433 is an equidigital number, since it uses as much as digits as its factorization.
23002411433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67503.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 23002411433 its reverse (33411420032), we get a palindrome (56413831465).
The spelling of 23002411433 in words is "twenty-three billion, two million, four hundred eleven thousand, four hundred thirty-three".
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