Base | Representation |
---|---|
bin | 1010011101100000011111… |
… | …11000010000110000110111 |
3 | 10000110011122001202122002212 |
4 | 11032300033320100300313 |
5 | 11003344404434304333 |
6 | 120531535351524035 |
7 | 4562664215206055 |
oct | 516601770206067 |
9 | 100404561678085 |
10 | 23004111244343 |
11 | 7369a97099509 |
12 | 26b642638961b |
13 | cab3807b4ba8 |
14 | 5975951851d5 |
15 | 29d5ca4c6448 |
hex | 14ec0fe10c37 |
23004111244343 has 2 divisors, whose sum is σ = 23004111244344. Its totient is φ = 23004111244342.
The previous prime is 23004111244339. The next prime is 23004111244421. The reversal of 23004111244343 is 34344211140032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23004111244343 - 22 = 23004111244339 is a prime.
It is a super-3 number, since 3×230041112443433 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23004111244333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11502055622171 + 11502055622172.
It is an arithmetic number, because the mean of its divisors is an integer number (11502055622172).
Almost surely, 223004111244343 is an apocalyptic number.
23004111244343 is a deficient number, since it is larger than the sum of its proper divisors (1).
23004111244343 is an equidigital number, since it uses as much as digits as its factorization.
23004111244343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 23004111244343 its reverse (34344211140032), we get a palindrome (57348322384375).
The spelling of 23004111244343 in words is "twenty-three trillion, four billion, one hundred eleven million, two hundred forty-four thousand, three hundred forty-three".
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