Base | Representation |
---|---|
bin | 10101011011001010… |
… | …111100010000101001 |
3 | 2012101012220012022211 |
4 | 111123022330100221 |
5 | 334103113301101 |
6 | 14322412445121 |
7 | 1443033304060 |
oct | 253312742051 |
9 | 65335805284 |
10 | 23004431401 |
11 | 9835446886 |
12 | 45601797a1 |
13 | 2227c811b3 |
14 | 11833231d7 |
15 | 8e98d7c51 |
hex | 55b2bc429 |
23004431401 has 4 divisors (see below), whose sum is σ = 26290778752. Its totient is φ = 19718084052.
The previous prime is 23004431369. The next prime is 23004431419. The reversal of 23004431401 is 10413440032.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 23004431401 - 25 = 23004431369 is a prime.
It is not an unprimeable number, because it can be changed into a prime (23004431491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1643173665 + ... + 1643173678.
It is an arithmetic number, because the mean of its divisors is an integer number (6572694688).
Almost surely, 223004431401 is an apocalyptic number.
It is an amenable number.
23004431401 is a deficient number, since it is larger than the sum of its proper divisors (3286347351).
23004431401 is an equidigital number, since it uses as much as digits as its factorization.
23004431401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3286347350.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 23004431401 its reverse (10413440032), we get a palindrome (33417871433).
The spelling of 23004431401 in words is "twenty-three billion, four million, four hundred thirty-one thousand, four hundred one".
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