Base | Representation |
---|---|
bin | 10101011011010011… |
… | …101001101010000111 |
3 | 2012101101012012011011 |
4 | 111123103221222013 |
5 | 334104204331003 |
6 | 14322533423051 |
7 | 1443061563253 |
oct | 253323515207 |
9 | 65341165134 |
10 | 23006714503 |
11 | 9836766143 |
12 | 4560a9aa87 |
13 | 22285a0446 |
14 | 1183759263 |
15 | 8e9bd946d |
hex | 55b4e9a87 |
23006714503 has 2 divisors, whose sum is σ = 23006714504. Its totient is φ = 23006714502.
The previous prime is 23006714491. The next prime is 23006714519. The reversal of 23006714503 is 30541760032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23006714503 - 213 = 23006706311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23006714603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11503357251 + 11503357252.
It is an arithmetic number, because the mean of its divisors is an integer number (11503357252).
Almost surely, 223006714503 is an apocalyptic number.
23006714503 is a deficient number, since it is larger than the sum of its proper divisors (1).
23006714503 is an equidigital number, since it uses as much as digits as its factorization.
23006714503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 31.
The spelling of 23006714503 in words is "twenty-three billion, six million, seven hundred fourteen thousand, five hundred three".
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