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23010220131181 is a prime number
BaseRepresentation
bin1010011101101011110111…
…11111110100001101101101
310000110202101210201020102221
411032311323333310031231
511003444412323144211
6120534425454315341
74563301463661553
oct516657377641555
9100422353636387
1023010220131181
117371641430618
1226b76501b8b51
13cabb152b642a
145979b4619bd3
1529d83696bc71
hex14ed7bff436d

23010220131181 has 2 divisors, whose sum is σ = 23010220131182. Its totient is φ = 23010220131180.

The previous prime is 23010220131109. The next prime is 23010220131193. The reversal of 23010220131181 is 18113102201032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22306020555625 + 704199575556 = 4722925^2 + 839166^2 .

It is a cyclic number.

It is not a de Polignac number, because 23010220131181 - 217 = 23010220000109 is a prime.

It is a super-2 number, since 2×230102201311812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23010220131881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11505110065590 + 11505110065591.

It is an arithmetic number, because the mean of its divisors is an integer number (11505110065591).

Almost surely, 223010220131181 is an apocalyptic number.

It is an amenable number.

23010220131181 is a deficient number, since it is larger than the sum of its proper divisors (1).

23010220131181 is an equidigital number, since it uses as much as digits as its factorization.

23010220131181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

The spelling of 23010220131181 in words is "twenty-three trillion, ten billion, two hundred twenty million, one hundred thirty-one thousand, one hundred eighty-one".