2301320001113 has 4 divisors (see below), whose sum is σ = 2630080001280. Its totient is φ = 1972560000948.

The previous prime is 2301320001089. The next prime is 2301320001133. The reversal of 2301320001113 is 3111000231032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2301320001113 - 2²² = 2301315806809 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2301320001091 and 2301320001100.

It is not an unprimeable number, because it can be changed into a prime (2301320001133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164380000073 + ... + 164380000086.

It is an arithmetic number, because the mean of its divisors is an integer number (657520000320).

Almost surely, 2^{2301320001113} is an apocalyptic number.

It is an amenable number.

2301320001113 is a deficient number, since it is larger than the sum of its proper divisors (328760000167).

2301320001113 is an equidigital number, since it uses as much as digits as its factorization.

2301320001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 328760000166.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 2301320001113 its reverse (3111000231032), we get a palindrome (5412320232145).

The spelling of 2301320001113 in words is "two trillion, three hundred one billion, three hundred twenty million, one thousand, one hundred thirteen".