Base | Representation |
---|---|
bin | 10101011011101101… |
… | …001111110100110001 |
3 | 2012101211211002110002 |
4 | 111123231033310301 |
5 | 334112414040213 |
6 | 14323333315345 |
7 | 1443202610606 |
oct | 253355176461 |
9 | 65354732402 |
10 | 23013424433 |
11 | 983a52943a |
12 | 4563195b55 |
13 | 2229aac60c |
14 | 11845c46ad |
15 | 8ea5b2658 |
hex | 55bb4fd31 |
23013424433 has 16 divisors (see below), whose sum is σ = 25843453056. Its totient is φ = 20378307840.
The previous prime is 23013424417. The next prime is 23013424459. The reversal of 23013424433 is 33442431032.
It is a cyclic number.
It is not a de Polignac number, because 23013424433 - 24 = 23013424417 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23013424396 and 23013424405.
It is not an unprimeable number, because it can be changed into a prime (23013424493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 458591 + ... + 506292.
It is an arithmetic number, because the mean of its divisors is an integer number (1615215816).
Almost surely, 223013424433 is an apocalyptic number.
23013424433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
23013424433 is a deficient number, since it is larger than the sum of its proper divisors (2830028623).
23013424433 is a wasteful number, since it uses less digits than its factorization.
23013424433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 964984.
The product of its (nonzero) digits is 20736, while the sum is 29.
Adding to 23013424433 its reverse (33442431032), we get a palindrome (56455855465).
The spelling of 23013424433 in words is "twenty-three billion, thirteen million, four hundred twenty-four thousand, four hundred thirty-three".
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