230244340112051 has 2 divisors, whose sum is σ = 230244340112052. Its totient is φ = 230244340112050.

The previous prime is 230244340112047. The next prime is 230244340112053. The reversal of 230244340112051 is 150211043442032.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 230244340112051 - 2² = 230244340112047 is a prime.

Together with 230244340112053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 230244340111999 and 230244340112017.

It is not a weakly prime, because it can be changed into another prime (230244340112053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115122170056025 + 115122170056026.

It is an arithmetic number, because the mean of its divisors is an integer number (115122170056026).

Almost surely, 2^{230244340112051} is an apocalyptic number.

230244340112051 is a deficient number, since it is larger than the sum of its proper divisors (1).

230244340112051 is an equidigital number, since it uses as much as digits as its factorization.

230244340112051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 230244340112051 its reverse (150211043442032), we get a palindrome (380455383554083).

The spelling of 230244340112051 in words is "two hundred thirty trillion, two hundred forty-four billion, three hundred forty million, one hundred twelve thousand, fifty-one".