Base | Representation |
---|---|
bin | 100001100001000100011… |
… | …011100011011100011001 |
3 | 22011012002111020122100212 |
4 | 201201010123203130121 |
5 | 300214024114410114 |
6 | 4522033152340505 |
7 | 325255460413313 |
oct | 41410433433431 |
9 | 8135074218325 |
10 | 2303250544409 |
11 | 808891983221 |
12 | 312475b44735 |
13 | 13927094a929 |
14 | 7d6995b67b3 |
15 | 3eda5c20b3e |
hex | 218446e3719 |
2303250544409 has 2 divisors, whose sum is σ = 2303250544410. Its totient is φ = 2303250544408.
The previous prime is 2303250544403. The next prime is 2303250544411. The reversal of 2303250544409 is 9044450523032.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2300075560000 + 3174984409 = 1516600^2 + 56347^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2303250544409 is a prime.
Together with 2303250544411, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2303250544403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1151625272204 + 1151625272205.
It is an arithmetic number, because the mean of its divisors is an integer number (1151625272205).
Almost surely, 22303250544409 is an apocalyptic number.
It is an amenable number.
2303250544409 is a deficient number, since it is larger than the sum of its proper divisors (1).
2303250544409 is an equidigital number, since it uses as much as digits as its factorization.
2303250544409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 41.
The spelling of 2303250544409 in words is "two trillion, three hundred three billion, two hundred fifty million, five hundred forty-four thousand, four hundred nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •