Base | Representation |
---|---|
bin | 1010011110010110100001… |
… | …11100011000111111101111 |
3 | 10000112221111202002212110021 |
4 | 11033023100330120333233 |
5 | 11004333312223224403 |
6 | 120553134101023011 |
7 | 4565042121534553 |
oct | 517132074307757 |
9 | 100487452085407 |
10 | 23033120133103 |
11 | 738032292aa43 |
12 | 26bbb813b4a67 |
13 | cb1024732922 |
14 | 598b47b17863 |
15 | 29e2270c78bd |
hex | 14f2d0f18fef |
23033120133103 has 4 divisors (see below), whose sum is σ = 23037779883168. Its totient is φ = 23028460383040.
The previous prime is 23033120133097. The next prime is 23033120133151. The reversal of 23033120133103 is 30133102133032.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 23033120133103 - 217 = 23033120002031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23033120133703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2329867618 + ... + 2329877503.
It is an arithmetic number, because the mean of its divisors is an integer number (5759444970792).
Almost surely, 223033120133103 is an apocalyptic number.
23033120133103 is a deficient number, since it is larger than the sum of its proper divisors (4659750065).
23033120133103 is an equidigital number, since it uses as much as digits as its factorization.
23033120133103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4659750064.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 23033120133103 its reverse (30133102133032), we get a palindrome (53166222266135).
The spelling of 23033120133103 in words is "twenty-three trillion, thirty-three billion, one hundred twenty million, one hundred thirty-three thousand, one hundred three".
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