23040113142433 has 4 divisors (see below), whose sum is σ = 24041857192128. Its totient is φ = 22038369092740.

The previous prime is 23040113142379. The next prime is 23040113142457. The reversal of 23040113142433 is 33424131104032.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-23040113142433 is a prime.

It is a super-2 number, since 2×23040113142433² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23040113142395 and 23040113142404.

It is not an unprimeable number, because it can be changed into a prime (23040113142833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500872024813 + ... + 500872024858.

It is an arithmetic number, because the mean of its divisors is an integer number (6010464298032).

Almost surely, 2^{23040113142433} is an apocalyptic number.

23040113142433 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

23040113142433 is a deficient number, since it is larger than the sum of its proper divisors (1001744049695).

23040113142433 is a wasteful number, since it uses less digits than its factorization.

23040113142433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1001744049694.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 23040113142433 its reverse (33424131104032), we get a palindrome (56464244246465).

The spelling of 23040113142433 in words is "twenty-three trillion, forty billion, one hundred thirteen million, one hundred forty-two thousand, four hundred thirty-three".