Base | Representation |
---|---|
bin | 1010011110101001010101… |
… | …00110001111100101110111 |
3 | 10000120220120012220011210202 |
4 | 11033110222212033211313 |
5 | 11010020000314231242 |
6 | 121001523444111115 |
7 | 4565550221016443 |
oct | 517245246174567 |
9 | 100526505804722 |
10 | 23043214211447 |
11 | 7384632761451 |
12 | 2701b1999549b |
13 | cb1c72a6c451 |
14 | 599424569823 |
15 | 29e61836a932 |
hex | 14f52a98f977 |
23043214211447 has 2 divisors, whose sum is σ = 23043214211448. Its totient is φ = 23043214211446.
The previous prime is 23043214211401. The next prime is 23043214211497. The reversal of 23043214211447 is 74411241234032.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23043214211447 - 26 = 23043214211383 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 23043214211447.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23043214211497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11521607105723 + 11521607105724.
It is an arithmetic number, because the mean of its divisors is an integer number (11521607105724).
Almost surely, 223043214211447 is an apocalyptic number.
23043214211447 is a deficient number, since it is larger than the sum of its proper divisors (1).
23043214211447 is an equidigital number, since it uses as much as digits as its factorization.
23043214211447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129024, while the sum is 38.
Adding to 23043214211447 its reverse (74411241234032), we get a palindrome (97454455445479).
The spelling of 23043214211447 in words is "twenty-three trillion, forty-three billion, two hundred fourteen million, two hundred eleven thousand, four hundred forty-seven".
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