Base | Representation |
---|---|
bin | 1010011110111001111100… |
… | …00101101001001011010111 |
3 | 10000121202120122200022021001 |
4 | 11033130332011221023113 |
5 | 11010141231033110112 |
6 | 121010000341004131 |
7 | 4566314204501521 |
oct | 517347605511327 |
9 | 100552518608231 |
10 | 23052131144407 |
11 | 7388399077132 |
12 | 27037a80b3647 |
13 | cb2a64257341 |
14 | 599a2c91aa11 |
15 | 29e98b0d9c57 |
hex | 14f73e1692d7 |
23052131144407 has 2 divisors, whose sum is σ = 23052131144408. Its totient is φ = 23052131144406.
The previous prime is 23052131144309. The next prime is 23052131144417. The reversal of 23052131144407 is 70444113125032.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23052131144407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23052131144417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11526065572203 + 11526065572204.
It is an arithmetic number, because the mean of its divisors is an integer number (11526065572204).
Almost surely, 223052131144407 is an apocalyptic number.
23052131144407 is a deficient number, since it is larger than the sum of its proper divisors (1).
23052131144407 is an equidigital number, since it uses as much as digits as its factorization.
23052131144407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 37.
Adding to 23052131144407 its reverse (70444113125032), we get a palindrome (93496244269439).
The spelling of 23052131144407 in words is "twenty-three trillion, fifty-two billion, one hundred thirty-one million, one hundred forty-four thousand, four hundred seven".
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