Base | Representation |
---|---|
bin | 1010011110111010000101… |
… | …10111001000001000011101 |
3 | 10000121202210020100211100021 |
4 | 11033131002313020020131 |
5 | 11010141412033200432 |
6 | 121010012321232141 |
7 | 4566316166252134 |
oct | 517350267101035 |
9 | 100552706324307 |
10 | 23052211225117 |
11 | 738842a2a2a38 |
12 | 270380aa92651 |
13 | cb2a77a15389 |
14 | 599a3940491b |
15 | 29e993157697 |
hex | 14f742dc821d |
23052211225117 has 2 divisors, whose sum is σ = 23052211225118. Its totient is φ = 23052211225116.
The previous prime is 23052211225027. The next prime is 23052211225213. The reversal of 23052211225117 is 71152211225032.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14750776774276 + 8301434450841 = 3840674^2 + 2881221^2 .
It is a cyclic number.
It is not a de Polignac number, because 23052211225117 - 215 = 23052211192349 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23052211225717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11526105612558 + 11526105612559.
It is an arithmetic number, because the mean of its divisors is an integer number (11526105612559).
Almost surely, 223052211225117 is an apocalyptic number.
It is an amenable number.
23052211225117 is a deficient number, since it is larger than the sum of its proper divisors (1).
23052211225117 is an equidigital number, since it uses as much as digits as its factorization.
23052211225117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 34.
The spelling of 23052211225117 in words is "twenty-three trillion, fifty-two billion, two hundred eleven million, two hundred twenty-five thousand, one hundred seventeen".
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