Base | Representation |
---|---|
bin | 1010011111001011000010… |
… | …11011100111111000101011 |
3 | 10000122122021121220220120110 |
4 | 11033211201123213320223 |
5 | 11010314032343342220 |
6 | 121014115454225403 |
7 | 4600060601034063 |
oct | 517454133477053 |
9 | 100578247826513 |
10 | 23061314043435 |
11 | 7391280630088 |
12 | 270552b4b5263 |
13 | cb3898884bc5 |
14 | 59a2603423a3 |
15 | 29ed27393be0 |
hex | 14f9616e7e2b |
23061314043435 has 32 divisors (see below), whose sum is σ = 37637856534528. Its totient is φ = 12053320622720.
The previous prime is 23061314043413. The next prime is 23061314043437. The reversal of 23061314043435 is 53434041316032.
It is not a de Polignac number, because 23061314043435 - 26 = 23061314043371 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23061314043393 and 23061314043402.
It is not an unprimeable number, because it can be changed into a prime (23061314043437) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16120371 + ... + 17492540.
It is an arithmetic number, because the mean of its divisors is an integer number (1176183016704).
Almost surely, 223061314043435 is an apocalyptic number.
23061314043435 is a deficient number, since it is larger than the sum of its proper divisors (14576542491093).
23061314043435 is a wasteful number, since it uses less digits than its factorization.
23061314043435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33613835.
The product of its (nonzero) digits is 311040, while the sum is 39.
Adding to 23061314043435 its reverse (53434041316032), we get a palindrome (76495355359467).
The spelling of 23061314043435 in words is "twenty-three trillion, sixty-one billion, three hundred fourteen million, forty-three thousand, four hundred thirty-five".
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