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230642260433 = 1317741712341
BaseRepresentation
bin1101011011001101011…
…0011001100111010001
3211001022212002210112222
43112303112121213101
512234323404313213
6253542224030425
722443346603154
oct3266326314721
9731285083488
10230642260433
11898a65a7a82
1238849762415
1318998788520
14b23d953c9b
155eed667808
hex35b35999d1

230642260433 has 4 divisors (see below), whose sum is σ = 248383972788. Its totient is φ = 212900548080.

The previous prime is 230642260421. The next prime is 230642260501. The reversal of 230642260433 is 334062246032.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 84754930129 + 145887330304 = 291127^2 + 381952^2 .

It is a cyclic number.

It is not a de Polignac number, because 230642260433 - 228 = 230373824977 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 230642260393 and 230642260402.

It is not an unprimeable number, because it can be changed into a prime (230642260633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8870856158 + ... + 8870856183.

It is an arithmetic number, because the mean of its divisors is an integer number (62095993197).

Almost surely, 2230642260433 is an apocalyptic number.

It is an amenable number.

230642260433 is a deficient number, since it is larger than the sum of its proper divisors (17741712355).

230642260433 is a wasteful number, since it uses less digits than its factorization.

230642260433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17741712354.

The product of its (nonzero) digits is 124416, while the sum is 35.

The spelling of 230642260433 in words is "two hundred thirty billion, six hundred forty-two million, two hundred sixty thousand, four hundred thirty-three".

Divisors: 1 13 17741712341 230642260433