23100000017 has 2 divisors, whose sum is σ = 23100000018. Its totient is φ = 23100000016.

The previous prime is 23099999939. The next prime is 23100000019. The reversal of 23100000017 is 71000000132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22693614736 + 406385281 = 150644^2 + 20159^2 .

It is a cyclic number.

It is not a de Polignac number, because 23100000017 - 2⁸ = 23099999761 is a prime.

It is a super-2 number, since 2×23100000017² (a number of 22 digits) contains 22 as substring.

Together with 23100000019, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 23099999947 and 23100000010.

It is not a weakly prime, because it can be changed into another prime (23100000019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11550000008 + 11550000009.

It is an arithmetic number, because the mean of its divisors is an integer number (11550000009).

Almost surely, 2^23100000017 is an apocalyptic number.

It is an amenable number.

23100000017 is a deficient number, since it is larger than the sum of its proper divisors (1).

23100000017 is an equidigital number, since it uses as much as digits as its factorization.

23100000017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42, while the sum is 14.

Adding to 23100000017 its reverse (71000000132), we get a palindrome (94100000149).

The spelling of 23100000017 in words is "twenty-three billion, one hundred million, seventeen", and thus it is an aban number.