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231001110210113 is a prime number
BaseRepresentation
bin110100100001100000100011…
…000111011110011001000001
31010021220111020112210202111122
4310201200203013132121001
5220234210233203210423
62135144240042522025
766441164566262165
oct6441404307363101
91107814215722448
10231001110210113
1167671025588611
1221aa9690506315
139bb84079b0a09
144108728a52ca5
151ba8d07cd08c8
hexd218231de641

231001110210113 has 2 divisors, whose sum is σ = 231001110210114. Its totient is φ = 231001110210112.

The previous prime is 231001110210109. The next prime is 231001110210137. The reversal of 231001110210113 is 311012011100132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 139050980992144 + 91950129217969 = 11791988^2 + 9589063^2 .

It is a cyclic number.

It is not a de Polignac number, because 231001110210113 - 22 = 231001110210109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 231001110210091 and 231001110210100.

It is not a weakly prime, because it can be changed into another prime (231001110210103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115500555105056 + 115500555105057.

It is an arithmetic number, because the mean of its divisors is an integer number (115500555105057).

Almost surely, 2231001110210113 is an apocalyptic number.

It is an amenable number.

231001110210113 is a deficient number, since it is larger than the sum of its proper divisors (1).

231001110210113 is an equidigital number, since it uses as much as digits as its factorization.

231001110210113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 231001110210113 its reverse (311012011100132), we get a palindrome (542013121310245).

The spelling of 231001110210113 in words is "two hundred thirty-one trillion, one billion, one hundred ten million, two hundred ten thousand, one hundred thirteen".