Base | Representation |
---|---|
bin | 100001100111010111011… |
… | …001110111111100100001 |
3 | 22011211112122211201220021 |
4 | 201213113121313330201 |
5 | 300321400344302040 |
6 | 4525112103313441 |
7 | 325615143156502 |
oct | 41472731677441 |
9 | 8154478751807 |
10 | 2310011322145 |
11 | 81074119563a |
12 | 31384214b881 |
13 | 139aaa515a27 |
14 | 7db3b460ba9 |
15 | 4014e53424a |
hex | 219d7677f21 |
2310011322145 has 4 divisors (see below), whose sum is σ = 2772013586580. Its totient is φ = 1848009057712.
The previous prime is 2310011322121. The next prime is 2310011322193. The reversal of 2310011322145 is 5412231100132.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 677432701969 + 1632578620176 = 823063^2 + 1277724^2 .
It is a cyclic number.
It is not a de Polignac number, because 2310011322145 - 217 = 2310011191073 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231001132210 + ... + 231001132219.
It is an arithmetic number, because the mean of its divisors is an integer number (693003396645).
Almost surely, 22310011322145 is an apocalyptic number.
It is an amenable number.
2310011322145 is a deficient number, since it is larger than the sum of its proper divisors (462002264435).
2310011322145 is an equidigital number, since it uses as much as digits as its factorization.
2310011322145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 462002264434.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 2310011322145 its reverse (5412231100132), we get a palindrome (7722242422277).
The spelling of 2310011322145 in words is "two trillion, three hundred ten billion, eleven million, three hundred twenty-two thousand, one hundred forty-five".
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