23101010113 has 4 divisors (see below), whose sum is σ = 23182639408. Its totient is φ = 23019380820.

The previous prime is 23101010087. The next prime is 23101010131. The reversal of 23101010113 is 31101010132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 23101010113 - 2¹³ = 23101001921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 23101010093 and 23101010102.

It is not an unprimeable number, because it can be changed into a prime (23101011113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40814223 + ... + 40814788.

It is an arithmetic number, because the mean of its divisors is an integer number (5795659852).

Almost surely, 2^23101010113 is an apocalyptic number.

It is an amenable number.

23101010113 is a deficient number, since it is larger than the sum of its proper divisors (81629295).

23101010113 is an equidigital number, since it uses as much as digits as its factorization.

23101010113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 81629294.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 23101010113 its reverse (31101010132), we get a palindrome (54202020245).

The spelling of 23101010113 in words is "twenty-three billion, one hundred one million, ten thousand, one hundred thirteen".