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231011453151 = 32181141811819
BaseRepresentation
bin1101011100100101011…
…0110000100011011111
3211002021120210201202100
43113021112300203133
512241102413000101
6254043013100143
722455451644603
oct3271126604337
9732246721670
10231011453151
1189a75a40a26
1238931327653
1318a2710155b
14b2769b9503
156020c92e86
hex35c95b08df

231011453151 has 12 divisors (see below), whose sum is σ = 335526766120. Its totient is φ = 153156763440.

The previous prime is 231011453149. The next prime is 231011453161. The reversal of 231011453151 is 151354110132.

231011453151 is a `hidden beast` number, since 2 + 3 + 10 + 114 + 531 + 5 + 1 = 666.

It is not a de Polignac number, because 231011453151 - 21 = 231011453149 is a prime.

It is a super-3 number, since 3×2310114531513 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (231011453131) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 70904281 + ... + 70907538.

Almost surely, 2231011453151 is an apocalyptic number.

231011453151 is a deficient number, since it is larger than the sum of its proper divisors (104515312969).

231011453151 is a wasteful number, since it uses less digits than its factorization.

231011453151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 141812006 (or 141812003 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 27.

Adding to 231011453151 its reverse (151354110132), we get a palindrome (382365563283).

The spelling of 231011453151 in words is "two hundred thirty-one billion, eleven million, four hundred fifty-three thousand, one hundred fifty-one".

Divisors: 1 3 9 181 543 1629 141811819 425435457 1276306371 25667939239 77003817717 231011453151