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2310240113 is a prime number
BaseRepresentation
bin1000100110110011…
…0111011101110001
312222000010100122122
42021230313131301
514212410140423
61021124244025
7111151500626
oct21154673561
95860110578
102310240113
11a86085655
12545840615
132aa81c0ac
1417cb7634d
15d7c458c8
hex89b37771

2310240113 has 2 divisors, whose sum is σ = 2310240114. Its totient is φ = 2310240112.

The previous prime is 2310240089. The next prime is 2310240157. The reversal of 2310240113 is 3110420132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1331301169 + 978938944 = 36487^2 + 31288^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2310240113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2310240091 and 2310240100.

It is not a weakly prime, because it can be changed into another prime (2310240013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155120056 + 1155120057.

It is an arithmetic number, because the mean of its divisors is an integer number (1155120057).

Almost surely, 22310240113 is an apocalyptic number.

It is an amenable number.

2310240113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2310240113 is an equidigital number, since it uses as much as digits as its factorization.

2310240113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2310240113 is about 48064.9572245727. The cubic root of 2310240113 is about 1321.9622089073.

Adding to 2310240113 its reverse (3110420132), we get a palindrome (5420660245).

The spelling of 2310240113 in words is "two billion, three hundred ten million, two hundred forty thousand, one hundred thirteen".