Base | Representation |
---|---|
bin | 100001100111101001010… |
… | …100111010111000011101 |
3 | 22011212022121122102200020 |
4 | 201213221110322320131 |
5 | 300323004333411331 |
6 | 4525202004222353 |
7 | 325625454045303 |
oct | 41475124727035 |
9 | 8155277572606 |
10 | 2310312013341 |
11 | 8108859a1362 |
12 | 31390699a9b9 |
13 | 139b278c6307 |
14 | 7db69374273 |
15 | 4016ab2cc96 |
hex | 219e953ae1d |
2310312013341 has 4 divisors (see below), whose sum is σ = 3080416017792. Its totient is φ = 1540208008892.
The previous prime is 2310312013327. The next prime is 2310312013343. The reversal of 2310312013341 is 1433102130132.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2310312013341 - 210 = 2310312012317 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2310312013343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 385052002221 + ... + 385052002226.
It is an arithmetic number, because the mean of its divisors is an integer number (770104004448).
Almost surely, 22310312013341 is an apocalyptic number.
It is an amenable number.
2310312013341 is a deficient number, since it is larger than the sum of its proper divisors (770104004451).
2310312013341 is an equidigital number, since it uses as much as digits as its factorization.
2310312013341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 770104004450.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 2310312013341 its reverse (1433102130132), we get a palindrome (3743414143473).
The spelling of 2310312013341 in words is "two trillion, three hundred ten billion, three hundred twelve million, thirteen thousand, three hundred forty-one".
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