Base | Representation |
---|---|
bin | 10101100001000100… |
… | …001110001100000001 |
3 | 2012122002222220222111 |
4 | 111201010032030001 |
5 | 334303423124441 |
6 | 14340304335321 |
7 | 1445344043221 |
oct | 254104161401 |
9 | 65562886874 |
10 | 23103333121 |
11 | 9886258140 |
12 | 4589314541 |
13 | 22425cbb1b |
14 | 119250a081 |
15 | 903422081 |
hex | 56110e301 |
23103333121 has 4 divisors (see below), whose sum is σ = 25203636144. Its totient is φ = 21003030100.
The previous prime is 23103333041. The next prime is 23103333139. The reversal of 23103333121 is 12133330132.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 23103333121 - 217 = 23103202049 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 23103333092 and 23103333101.
It is not an unprimeable number, because it can be changed into a prime (23103333821) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1050151495 + ... + 1050151516.
It is an arithmetic number, because the mean of its divisors is an integer number (6300909036).
Almost surely, 223103333121 is an apocalyptic number.
It is an amenable number.
23103333121 is a deficient number, since it is larger than the sum of its proper divisors (2100303023).
23103333121 is a wasteful number, since it uses less digits than its factorization.
23103333121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2100303022.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 23103333121 its reverse (12133330132), we get a palindrome (35236663253).
The spelling of 23103333121 in words is "twenty-three billion, one hundred three million, three hundred thirty-three thousand, one hundred twenty-one".
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