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23104412400 = 243527323613
BaseRepresentation
bin10101100001001000…
…010101101011110000
32012122012000202110210
4111201020111223300
5334304212144100
614340343424120
71445356156626
oct254110255360
965565022423
1023104412400
119886925003
124589755040
1322428b9154
14119270b516
15903586c50
hex561215af0

23104412400 has 180 divisors, whose sum is σ = 75059643048. Its totient is φ = 6075095040.

The previous prime is 23104412351. The next prime is 23104412447. The reversal of 23104412400 is 421440132.

It is a super-3 number, since 3×231044124003 (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 6392994 + ... + 6396606.

Almost surely, 223104412400 is an apocalyptic number.

23104412400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 23104412400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (37529821524).

23104412400 is an abundant number, since it is smaller than the sum of its proper divisors (51955230648).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

23104412400 is a wasteful number, since it uses less digits than its factorization.

23104412400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3780 (or 3696 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 21.

Adding to 23104412400 its reverse (421440132), we get a palindrome (23525852532).

The spelling of 23104412400 in words is "twenty-three billion, one hundred four million, four hundred twelve thousand, four hundred".