2311001131213 has 4 divisors (see below), whose sum is σ = 2311061922720. Its totient is φ = 2310940339708.

The previous prime is 2311001131211. The next prime is 2311001131223. The reversal of 2311001131213 is 3121311001132.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2311001131213 - 2¹ = 2311001131211 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2311001131211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30338695 + ... + 30414772.

It is an arithmetic number, because the mean of its divisors is an integer number (577765480680).

Almost surely, 2^{2311001131213} is an apocalyptic number.

It is an amenable number.

2311001131213 is a deficient number, since it is larger than the sum of its proper divisors (60791507).

2311001131213 is an equidigital number, since it uses as much as digits as its factorization.

2311001131213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60791506.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 2311001131213 its reverse (3121311001132), we get a palindrome (5432312132345).

The spelling of 2311001131213 in words is "two trillion, three hundred eleven billion, one million, one hundred thirty-one thousand, two hundred thirteen".