Base | Representation |
---|---|
bin | 100001101000010100001… |
… | …100111001100110010111 |
3 | 22011221011202011120022021 |
4 | 201220110030321212113 |
5 | 300330443010044343 |
6 | 4525401221514011 |
7 | 325652340125056 |
oct | 41502414714627 |
9 | 8157152146267 |
10 | 2311031331223 |
11 | 811114a3554a |
12 | 313a87872907 |
13 | 139c1093a4b4 |
14 | 7dbd6ada39d |
15 | 401add690ed |
hex | 21a14339997 |
2311031331223 has 2 divisors, whose sum is σ = 2311031331224. Its totient is φ = 2311031331222.
The previous prime is 2311031331199. The next prime is 2311031331241. The reversal of 2311031331223 is 3221331301132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2311031331223 - 29 = 2311031330711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2311031331253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155515665611 + 1155515665612.
It is an arithmetic number, because the mean of its divisors is an integer number (1155515665612).
Almost surely, 22311031331223 is an apocalyptic number.
2311031331223 is a deficient number, since it is larger than the sum of its proper divisors (1).
2311031331223 is an equidigital number, since it uses as much as digits as its factorization.
2311031331223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 2311031331223 its reverse (3221331301132), we get a palindrome (5532362632355).
The spelling of 2311031331223 in words is "two trillion, three hundred eleven billion, thirty-one million, three hundred thirty-one thousand, two hundred twenty-three".
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