2311041121 has 2 divisors, whose sum is σ = 2311041122. Its totient is φ = 2311041120.

The previous prime is 2311041119. The next prime is 2311041133. The reversal of 2311041121 is 1211401132.

2311041121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2310148096 + 893025 = 48064^2 + 945^2 .

It is a cyclic number.

It is not a de Polignac number, because 2311041121 - 2¹ = 2311041119 is a prime.

It is a super-2 number, since 2×2311041121² = 10681822125905873282, which contains 22 as substring.

Together with 2311041119, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 2311041095 and 2311041104.

It is not a weakly prime, because it can be changed into another prime (2311041101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155520560 + 1155520561.

It is an arithmetic number, because the mean of its divisors is an integer number (1155520561).

Almost surely, 2^2311041121 is an apocalyptic number.

It is an amenable number.

2311041121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2311041121 is an equidigital number, since it uses as much as digits as its factorization.

2311041121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 2311041121 is about 48073.2890595183. The cubic root of 2311041121 is about 1322.1149751272.

Adding to 2311041121 its reverse (1211401132), we get a palindrome (3522442253).

The spelling of 2311041121 in words is "two billion, three hundred eleven million, forty-one thousand, one hundred twenty-one".